9x^2-47x=0

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Solution for 9x^2-47x=0 equation: 



9x^2-47x=0

a = 9; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·9·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*9}=\frac{0}{18}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*9}=\frac{94}{18}
=5+2/9
$

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